4(2x-1)=5x^2+17

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Solution for 4(2x-1)=5x^2+17 equation: 



4(2x-1)=5x^2+17

We move all terms to the left:

4(2x-1)-(5x^2+17)=0

We multiply parentheses

8x-(5x^2+17)-4=0

We get rid of parentheses

-5x^2+8x-17-4=0

We add all the numbers together, and all the variables

-5x^2+8x-21=0

a = -5; b = 8; c = -21;
Δ = b2-4ac
Δ = 82-4·(-5)·(-21)
Δ = -356
Delta is less than zero, so there is no solution for the equation

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